Substitute t = Log(x)/7
Integral is then proportional to:
Integral of dx/[x^2 + 13 x + 36] =
Integral of dx/[(x+4)(x+9)]
1/[(x+4)(x+9)] = A/(x+4) + B/(x+9)
Multiply both sides by x+4 and take limit x to -4:
1/5 = A
Multiply both sides by x+9 and take limit x to -9:
1/5 = A
-1/5 = B
Thank you so much.
I've reached the last step of
But how do I substitute the variable 't' back in?
t = Log(x)/7 ---->
x = exp(7 t)
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