Posted by Sugarplum on .
A player passes a basketball to another player who catches it at the same level from which it was thrown. The initial speed of the ball is 7.1 m/s, and it travels a distance of 4.6 m. What was (a) the initial direction of the ball and (b) its time of flight?

physics projectile motion 
drwls,
Use this relationship between distance travelled (D) and angle (A):
D = 2(V^2/g)sinA cos A
= (V^2/g)sin(2A)
You know V, g, and D and so can solve for the angle 2A. Then divide 2A by 2. That will give you the angle A.
For the time of flight T,
V cos A*T = 4.6 m 
physics projectile motion 
MEL,
A) 32 degrees
B)0.76 seconds