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September 30, 2014

September 30, 2014

Posted by **Sean** on Thursday, March 13, 2008 at 10:10pm.

- Physics -
**Damon**, Thursday, March 13, 2008 at 10:43pmIt falls a distance h with zero initial velocity down

so

h = (1/2) (9.8) t^2 = 4.9 t^2

tan 30 = h/d where d is horizontal distance to point hit on floor so d = h/.577 = 1.73 h

d = 4.2 t

so

4.2 t = 1.73 h

t = .412 h

then

h = 4.9 t^2 = 4.9 (.412^2)(h^2)

h = .831 h^2

h = 1.20 meters

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