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March 31, 2015

March 31, 2015

Posted by **Kally** on Thursday, March 13, 2008 at 9:23pm.

x^-5 y^7/x^-2 y^5

y^2/x^3

x^3=0

- Algebra -
**Reiny**, Thursday, March 13, 2008 at 9:30pmyour x^-5 y^7/x^-2 y^5 should have said

x^-5 y^7/(x^-2 y^5) then it would be

y^2/x^3 as you had,

but I don't see what the x^3=0 in your last line is supposed to be.

Is it supposed to say x^3 is not equal to zero??

then it should be placed after you second last line as a restriction.

- Algebra -
**Kally**, Thursday, March 13, 2008 at 9:43pmI meant to put y^2/x^3 as my answer. Is that correct?

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