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March 29, 2017

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Can someone tell me if I am right?

Factor by group

20x^2-12x=15x-9
20x^2+3x+9
(4x+3)(5x-3) answer

  • Algebra - ,

    20x^2-27x-9

  • Algebra - ,

    meant +9 and then do the rest.

  • Algebra - ,

    yes, you are right, but you should have maintained your equation.
    20x^2+3x+9 = 0
    (4x+3)(5x-3) = 0

    You could have tested your answer by expanding it to get back the
    20x^2+3x+9 = 0

  • Algebra - ,

    oops, just looked at your second line and assumed you would have had that one correct,
    Chad is correct above.

  • Algebra - ,

    So my second line should be:

    20x^2-27x+9=0

  • Algebra - ,

    yes, and it factors to
    (5x-3)(4x-3) = 0

    test the answer by expanding it

  • Algebra - ,

    Sorry, I put and = when it should have been a +! Is the one below right?


    20x^2-12x+15x-9

    20x^2-12x+15x-9

    = 20x^2+3x-9
    = (4x+3)(5x-3)

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