.5=e^(-20t)
I am assuming this involves logs but we did't really learn logs. Anyone care to walk me through with a calculator. Have the Ti-83
nevermind i got it. Thanks anyway.
Thanks for letting us know.
To solve the equation 0.5 = e^(-20t) using a calculator, you can follow these steps:
1. Turn on your TI-83 calculator.
2. Press the "2nd" button and then the "ln" button to access the natural logarithm function.
3. Enter the value of 0.5 by typing "0.5".
4. Press the right arrow button to move to the next part of the equation.
5. Enter "e^(-20t)" by typing "e^( - 20 * t)".
6. Press the "Enter" key to see the result.
The calculator will display the value of "t" that satisfies the equation.
However, if you haven't learned about logarithms yet, I can explain the process behind solving this equation using logarithms.
Let's start by taking the natural logarithm (ln) of both sides of the equation:
ln(0.5) = ln(e^(-20t))
Using logarithm properties, we can simplify the equation further. The log of the base raised to an exponent is equal to the exponent times the log of the base:
ln(0.5) = -20t * ln(e)
Now, since ln(e) is equal to 1, the equation simplifies to:
ln(0.5) = -20t
To isolate "t", divide both sides of the equation by -20:
ln(0.5) / -20 = t
By evaluating the left side of the equation, you can find the value of "t" using a calculator.