Posted by **Anonymous** on Thursday, March 13, 2008 at 3:56pm.

Consider a skateboarder who starts from rest at the top of a 12.5m-long ramp that is inclined at an angle of 15.0degrees to the horizontal. Assuming that the skateboarder's acceleration is g sin 15.0degrees, find his speed when he reaches the bottom of the ramp in 3.00 seconds

- Physics -
**drwls**, Thursday, March 13, 2008 at 7:59pm
That would be V = a t, where a is the acceleration rate (which is given) and t = 3.00 s. Using this method, I get

V = a t = 7.6 m/s

But they also give you the length of the ramp X, and the acceleration rate. From that, one gets

V = sqrt (2 a X) = 8.0 m/s

They have given you more data than you need and the data are somewhat inconsistent.

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