Posted by **Anonymous** on Thursday, March 13, 2008 at 3:53pm.

A ball is thrown from the top edge of a building with initial velocity components of 15m/s(up) vertically and 20m/s horizontally. It strikes ground 140m from the base of the building. What is the height of the building?

I tried using V2^2 = V1^2 + 2ad and it gave me 11.25 which I know is wrong. How would I calculate this?

## Answer This Question

## Related Questions

- Physics - A ball is thrown from the top edge of a building with initial velocity...
- Physics - A ball is thrown from the top edge of a building with initial velocity...
- Physics - A ball is thrown horizontally from the top of a building 45.2 m high. ...
- physics - a ball is thrown horizontally from the top of a building 35m. high. ...
- Physics - From the window of a building, a ball is tossed from a height y0 above...
- Physics - From the window of a building, a ball is tossed from a height y0 above...
- Physics - From the window of a building, a ball is tossed from a height y 0 ...
- physics - A ball is thrown horizontally with an initial velocity of 20.0 m/s ...
- Physics - A ball thrown horizontally from the top of a 13m high building strikes...
- Physics - An object is thrown from the top edge of a building at a speed of 21....

More Related Questions