Algebra
posted by G .
My book uses the slope yintercept method for graphing.
I am trying to graph the following:
y>3/2x5/2
(sign > is greater then or equal to)
The way I understand it I would start on the Y axis at 0 and go down 5 and then to the right 2 for the 5/2. Then I would go up 3 and to the right 2 for the 3/2. The book shows(0,3/2) and (2,7/2) as the coordinates. I have tried several different ways. I do not arrive at these coordinates.

No, the first step in your process is wrong.
The 5/2 IS the yintercept and 5/2 is 2.5
So you are at (0,2.5), now go up 3 and to the right 2, for the second point (2,0.5)
In fraction form these points should be
(0, 5/2) and (2,1/2)
Join them with a solid line, and shade in the region above the line.
Unless you typed the inequation incorrectly, the book answers you supplied are wrong. 
Thank you for your response.
This is a rough graph with the exact coordinates stated in the book.
Y


.(0,3/2)

0 ' ' ' ' 'X


 .(2,7/2)

 
My point was and my point still is that the book is wrong if these points are supposed to satisfy the "equation" part of the inequality.
The points I gave you DO satisfy the equation part of the inequality, thus they establish the boundary of the region you want.