Hello,
I need a little help with the following question.
Thank You,
My answer: either A or B I am not sure
An object is located 51 mm from a diverging lens. The object has a height of 13 mm and the image height is 3.5 mm. How far in front of the lens is the image located?
A. 1.12mm
B. 13.7mm
C. 51mm
D. 189mm
Solve this:
|Do/Di| = magnification = |3.5/13|
= 0.269
I use absolute value signs because Di, the image location, is actually negative, since the image is on the same side of the lens as the object.
Since Do = 51, Di = 0.269*51 = 13.7 mm