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Posted by on Wednesday, March 12, 2008 at 11:39pm.

I need a little help with the following question.
Thank You,

My answer: either A or B I am not sure

An object is located 51 mm from a diverging lens. The object has a height of 13 mm and the image height is 3.5 mm. How far in front of the lens is the image located?

A. 1.12mm
B. 13.7mm
C. 51mm
D. 189mm

  • Physical Science - , Wednesday, March 12, 2008 at 11:57pm

    Solve this:

    |Do/Di| = magnification = |3.5/13|
    = 0.269

    I use absolute value signs because Di, the image location, is actually negative, since the image is on the same side of the lens as the object.

    Since Do = 51, Di = 0.269*51 = 13.7 mm

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