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Posted by on Tuesday, March 11, 2008 at 11:31pm.

Calculate the probability that 3 or fewer rainy days occur during the next 15 days. The probability any day is rainy is .2.

For this question I tried using binomial distribution by setting x = 0, 1, 2, 3. p=.2 and n =15. After doing all of them, Do add the probabilities to get the answer?

  • Statistical Methods - , Wednesday, March 12, 2008 at 2:13am

    To get the probability that all events would occur, you need to multiply the probability of each of the individual events.

    The probablitiy of no rainy days is .8^15.

    The probability of one rainy day is .2 * .8^14.

    The probability of two rainy days is .2^2 * .8^13.

    The probability of three rainy days is .2^3 * .8^12.

    The probability of being either one or the other of these four probabilities is found by adding the four products above.

    I hope this helps. Thanks for asking.

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