What is the cenrtipetal force that allows a car to move around a sharp curve in a roadway?
Since this is not my area of expertise, I searched Google under the key words "centripetal force car" to get these possible sources:
http://www.glenbrook.k12.il.us/gbssci/Phys/Class/circles/u6l1c.html
http://www.batesville.k12.in.us/Physics/PhyNet/Mechanics/Circular%20Motion/turning_a_car.htm
http://www.teachersdomain.org/resources/phy03/sci/phys/mfw/centrip/index.html
http://en.wikipedia.org/wiki/Centrifugal_force
http://hyperphysics.phy-astr.gsu.edu/HBASE/corf.html
Use <Find> command within the sites to find "centripetal."
In the future, you can find the information you desire more quickly, if you use appropriate key words to do your own search.
I hope this helps. Thanks for asking.
well the answer is that if it is on a dry road then it will do a sharp turn, but if it is on a wet road it will slip away.
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The centripetal force is the force that allows a car to move around a sharp curve in a roadway. It acts towards the center of the curve and keeps the car from moving in a straight line off the road. The centripetal force is supplied by a combination of friction between the car's tires and the road and the car's own weight.
To calculate the centripetal force, you can use the following formula:
Fc = (m * v^2) / r
where Fc is the centripetal force, m is the mass of the car, v is the velocity of the car, and r is the radius of the curve.
To apply this formula, you need to know the values of the car's mass, velocity, and the radius of the curve. The mass of the car can be obtained from the car's specifications or by weighing it. The velocity can be measured using a speedometer or estimated based on known factors such as the time it takes to traverse the curve. The radius of the curve can usually be obtained from the roadway's design or by measuring it using appropriate tools.
By plugging in these values into the formula, you can calculate the centripetal force that allows the car to move around the sharp curve in the roadway.