Posted by Bretagne on Tuesday, March 11, 2008 at 7:12pm.
I know that the area of each rectangle is 8",32" and 81"
Do you mean the areas of the rectangles are in inches or in square feet? Is one rectangle about 2 ft by 4 ft -- thus 8 square feet?
Please clarify and we'll be glad to help you.
oo the area is in inches. yes the rectangles are something like that.
Rectangle one: 4 x 2 = 8inches (area)
Rectangle two: 8 x 4 = 32inches (area)
Rectangle three: 9 x 9 = 81inches (area)
sorry for any confusion
This is a mighty small pantry -- when the largest rectangle, 9" x 9", is smaller than an 8 1/2" x 11" sheet of notebook paper. The three rectangles of the pantry together would fit on two pieces of notebook paper.
I've seen many tiles that measured 6 inches on one side. If that's the size tile used in your problem, then you'd have to cut them in tiny pieces to fit your very small rectangles.
Thats what I was thinking but my teacher keep saying inches. Maybe she meant feet. I'm not sure.
I'm sure she means feet. I just measured my cell phone and it covers an area of about 8 square inches since it measures about 2 inches by 4 inches.
Is it possible that the scale on the drawing of the rectangles is 1" = 1'?
Let's assume that the rectangles of the pantry are actually in feet, not inches.
The smallest rectangle, then, measures 2 feet by 4 feet -- or 24 inches by 48 inches. Dividing 24 by 6 gives you 4 tiles across. Dividing 48 by 6 gives you 8 tiles down. 4 * 8 = 32 tiles for the smallest rectangle.
Rectangle two: 4' by 8' = 48" by 96". This rectangle then has 8 tiles across and 16 tiles down. Multiply: 8 * 16 to find the number of tiles.
Do the same calculations for the largest rectangle. Add the number of tiles together and then figure their cost.
If you post your answer, I'll be glad to check it.
so 484 tiles are needed to tile floor and it would cost $396.88?
Yes!!! You're right!
By the way, I think this is for a kitchen AND a pantry. And the price is reasonable for this size area.
Congratulations on hanging in there til you solved this problem! :-)