1. If 36.23 mL of potassium permanganate solution is required to titrate 1.041 g of FAS (FeSO4(NH4)2SO4 * 6 H2O, molar mass = 342.0 g), calculate the molarity of KMnO4.
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To calculate the molarity of KMnO4, we can use the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
First, we need to find the moles of FAS (FeSO4(NH4)2SO4 * 6 H2O). We can use the formula:
moles = mass / molar mass
Given that the mass of FAS is 1.041 g and the molar mass is 342.0 g, we can calculate the moles of FAS:
moles of FAS = 1.041 g / 342.0 g/mol
Next, we'll use the balanced chemical equation between KMnO4 and FAS to determine the mole ratio. The balanced equation is:
10 FAS + 2 KMnO4 + 8 H2SO4 --> 5 Fe2(SO4)3 + 2 MnSO4 + 8 H2O + K2SO4 + 5 (NH4)2SO4
From the balanced equation, we can see that the mole ratio between KMnO4 and FAS is 2:10. This means that for every 2 moles of KMnO4, we need 10 moles of FAS.
Now, we can calculate the moles of KMnO4:
moles of KMnO4 = (2/10) * moles of FAS
Next, we need to convert the volume of KMnO4 solution from mL to liters:
volume of KMnO4 solution = 36.23 mL / 1000 mL/L
Finally, we can calculate the molarity:
Molarity of KMnO4 = moles of KMnO4 / volume of KMnO4 solution
Substitute the values we obtained into the equation above, and you'll find the molarity of KMnO4.