Posted by Julie on Monday, March 10, 2008 at 8:57pm.
i have a couple questions
what are the least common multiples of these number sets (30,65) (66,55,44) (29,58,4)(20,55)(180,252) and 21,16
then i need someone to solve these inequalitys
x7<8 3t<15 3w>30 4n+8<24 6y+1<19
2r8>6 b5>2 2y+1<5 4x6>10
thanks in advance

Math  Reiny, Monday, March 10, 2008 at 11:29pm
I will do one for you:
(66,55,44)
66 = 11*3*2
55 = 11*5
44 = 11*2*2
So we will need 11*2*2*3*5 = 660
do the others the same way
I will do the last of the second batch
4x6>10
4x > 10 + 6
4x > 4
x > 1
There is only one thing you have to keep in mind.
If in the last step you either multiply or divide by a negative, the inequality sign has to be reversed.
e.g.
3x > 15
x < 5