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April 16, 2014

April 16, 2014

Posted by **Jessica** on Monday, March 10, 2008 at 8:43pm.

a. the force provided by the cable

b. the horizontal and vertical forces exerted on the beam by the pole

- Physics -
**drwls**, Monday, March 10, 2008 at 8:56pmAdd up the horizonal and vertical forces on the floodlamp separately. The cable exerts a tenstion force T and the pole exerts a compression force (push), P.

T sin 30 = M g

T cos 30 = P

Solve these two equations for the two unknowns. Here would be a good way to start:

tan 30 = M g /P

- Physics -
**drwls**, Monday, March 10, 2008 at 11:01pmI forgot not address part b or your problem. The horizontal force that the pole exerts on the floodlight is equal and opposite to the force the pole exerts on the beam. There is no vertical force, since the beam is assumed to be weightless and the beam support points are assumed to be frictionless, as if hinged.

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