Monday

March 2, 2015

March 2, 2015

Posted by **Jessica** on Monday, March 10, 2008 at 8:43pm.

a. the force provided by the cable

b. the horizontal and vertical forces exerted on the beam by the pole

- Physics -
**drwls**, Monday, March 10, 2008 at 8:56pmAdd up the horizonal and vertical forces on the floodlamp separately. The cable exerts a tenstion force T and the pole exerts a compression force (push), P.

T sin 30 = M g

T cos 30 = P

Solve these two equations for the two unknowns. Here would be a good way to start:

tan 30 = M g /P

- Physics -
**drwls**, Monday, March 10, 2008 at 11:01pmI forgot not address part b or your problem. The horizontal force that the pole exerts on the floodlight is equal and opposite to the force the pole exerts on the beam. There is no vertical force, since the beam is assumed to be weightless and the beam support points are assumed to be frictionless, as if hinged.

**Answer this Question**

**Related Questions**

maths - the floodlight is 6.1m tall. Jonny's height is unknown,though his shadow...

Statistics - The length of time it takes college students to find a parking spot...

Math for educators - The length of time it takes college students to find a ...

Statistics - If we know that the length of time it takes a college student to ...

Calculus - a college is planning to construct a new parking lot. the parking lot...

Calculus - a college is planning to construct a new parking lot. the parking lot...

geometry - A parking lot has seventy-three parking spaces numbered from 1 to 73...

MATHS - Could you please help? The Christmas tree store has a parking lot that ...

MATHS - Could you please help? The Christmas tree store has a parking lot that ...

math - a rectangular parking lot is 110 yards long and 45 yard wide it costs ...