Posted by Spencer on Monday, March 10, 2008 at 7:50pm.
Give up - this question is impossible.
roflcopter
Physics2212 students... lets all protest against mastering physics.
Consider the fractional error as
a = (V-V_v)/V
where a is equal to the 0.03 (because in this question the percent error is 3.00%)
You should know from Kirchhoff's rule that the Electric potential difference is
V=I(R_b+R_v)
You also found out that Elec. Poten. diff. with only the voltmeter as resistance is
V_v =IR_v
You plug in the Voltage equations to the first equation for the error and play a little with algebra you get the ratio as
R_b/R_v = (1/(1-a))-1
Got me the right answer. ;)
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