Friday

October 31, 2014

October 31, 2014

Posted by **Anonymous** on Monday, March 10, 2008 at 7:25pm.

20) For each of the following, find a normal vector, a direction vector, and a point of each line.

Note, normal vector means perpendicular to the direction vector.

a) 3x - 6y = 14

TEXTBOOK ANSWER:

normal vector = (1 , -2)

direction vector = (2 , 1)

point on the line = [(14/3) , 0]

-----------

21) Find vector, parametric, and symmetric equations of the following lines.

a) -4x + 6y + 9 = 0

TEXTBOOK ANSWER:

Vector Equation -> r = [0 , (-3/2)] + t(3 , 2)

Parametric Equation -> x = 3t and y = 2t - (3/2)

Symmetric Equation -> (x/3) = [y + (3/2)] / 2

**Answer this Question**

**Related Questions**

Discrete Math: Equations of Line in a Plane - I'm stuck on these questions. Can ...

Calc problem - Consider the function y=(kx)/(x-k) a. Show that y is symmetric ...

pre algebra - please show me step by step how to solve the following equation -...

math - Can someone please show me step by step how to solve this, I've been ...

L Pre-Cal - Hey! I'm getting stuck on how to solve this system of linear ...

Math - If y varies directly as x and y=3 when x=10, find x when y=8? Can you ...

8th Grade Math - How do you solve this equations? (xy^-3)^-5 (3x^4)(4x^12) ab^-6...

algebra - what is the solution of the following system {3x + 3y =10 {-9x-9 =-30 ...

Physics - I'm trying to rearange this 0 = Xo + 2^-1 a t^2 for t I've been told ...

Math - I am really have a tough time trying to solve this problem. I think my ...