Posted by **Gamel** on Monday, March 10, 2008 at 2:12am.

Suppose that an object is 100 lbs when it is at sea level. find the value of c that makes the equation true. (Sea level is 3963 miles from the center of the earth.) Use the value of c you found in the previous question to determin how much the object would weight in the Death valley (282 feet below sea level

- Math -
**drwls**, Monday, March 10, 2008 at 7:29am
You need to show the equation you are referring to, that has a constant c in it, which you are supposed to make true.

I will assume the equation is, for the 100# object in question,

W = C/R^2

where R is the diatance of the object from the center of the Earth in miles and W is in lb.

C = W R^2 = 100*3963^2 = 1.5705*10^9 lb

*mile^2

At 282 ft below sea level, the distance from the center of the earth is reduced by 282/5280 = 0.0534 miles, so the new weight W' is

W' = C/R^2

= 1.5705*10^9 lb /(3963-.0534)^2

= 100.064 lb

- mekygq lhkqe -
**mekygq lhkqe**, Sunday, February 1, 2009 at 2:15pm
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