Posted by tim on Sunday, March 9, 2008 at 7:56pm.
I have a feeling you meant to type
2^n x 4^(n+1) or else the +1 would be a nuisance dangling term
change the last factor
4^(n+1) into [2^2]^(n+1) = 2^(2n+2)
so now you have
(2^n)(2^(2n+2))
= 2^(3n+2)
thanx,
actually the site cut off my question, what i tried to type was
2^n x 4^(n+1)
/
8^(n-2)
then I am sure you can finish the question if your realize that
8^(n-2)
= [2^3]^(n-2)
= 2^(3n-6)
thanks for the help, i appreciate it, i was unsure of where iwas going wrong, it was just my brackets i mucked up, thanx.
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