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February 1, 2015

February 1, 2015

Posted by **tim** on Sunday, March 9, 2008 at 7:56pm.

change all bases to 2 then simplify fully

2^n x 4^n+1

8^n-2

(note that i cannot put the division line thingo in)

prove that:

a^m/n = n(outside radical sign)a^m (inside radical sign)

i dont know if you can understand that??? if not i will post a link 2 a word doc...

thanx 4 ur help!! :):)

- algebra -
**Reiny**, Sunday, March 9, 2008 at 8:06pmI have a feeling you meant to type

2^n x 4^(n+1) or else the +1 would be a nuisance dangling term

change the last factor

4^(n+1) into [2^2]^(n+1) = 2^(2n+2)

so now you have

(2^n)(2^(2n+2))

= 2^(3n+2)

- algebra -
**tim**, Sunday, March 9, 2008 at 8:26pmthanx,

actually the site cut off my question, what i tried to type was

2^n x 4^(n+1)

/

8^(n-2)

- algebra -
**Reiny**, Sunday, March 9, 2008 at 9:03pmthen I am sure you can finish the question if your realize that

8^(n-2)

= [2^3]^(n-2)

= 2^(3n-6)

- algebra -
- algebra -
**tim**, Sunday, March 9, 2008 at 10:50pmthanks for the help, i appreciate it, i was unsure of where iwas going wrong, it was just my brackets i mucked up, thanx.

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