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December 21, 2014

December 21, 2014

Posted by **Anonymous** on Sunday, March 9, 2008 at 3:28pm.

(4y^3-8y)/(y^2-2y)

- algebra...Please help! -
**drwls**, Sunday, March 9, 2008 at 4:22pmFind the y values for which the denominator is zero. There are two of them, 0 and 2

Actually, the fraction is well behaved even in the limiting cases, because

(4y^3-8y)/(y^2-2y) = 4y

- algebra...Please help! -
**Anonymous**, Sunday, March 9, 2008 at 4:27pmthanks, that helped a lot!!

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