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algebra

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use the quadratic formula to solve the equation
4x^2-7x-2=0

  • algebra - ,

    Your equation is already in the form ax^2 + bx + c = 0

    In your case,

    a = 4, b = -7 and c = -2.

    The quadratic formula for the solution values of x, which you should memorize or learn to derive, is

    x = [-b +/- sqrt (b^2-4ac)]/2a

    It would good practice for you to do the final alculation yourself

    b^2-4ac = 81 in this case, and has a square root that is an integer, making the answer rather easy to write down.

  • algebra - ,

    x = -b/2a +/- (1/2a)sqrt(b^2 - 4 a c)
    a = 4
    b = -7
    c = -2

    x = 7/8 +/- (1/8) sqrt ( 49 + 32)
    x = 7/8 +/- (1/8) sqrt (81)
    lucky (9*9)=81
    so
    x = 7/8 +/- 9/8
    x = 16/8 or -2/8 wow, nice polite numbers
    so
    x = 2 or - 1/4

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