Posted by Hokoslavia on Sunday, March 9, 2008 at 1:17pm.
Your equation is already in the form ax^2 + bx + c = 0
In your case,
a = 4, b = -7 and c = -2.
The quadratic formula for the solution values of x, which you should memorize or learn to derive, is
x = [-b +/- sqrt (b^2-4ac)]/2a
It would good practice for you to do the final alculation yourself
b^2-4ac = 81 in this case, and has a square root that is an integer, making the answer rather easy to write down.
x = -b/2a +/- (1/2a)sqrt(b^2 - 4 a c)
a = 4
b = -7
c = -2
x = 7/8 +/- (1/8) sqrt ( 49 + 32)
x = 7/8 +/- (1/8) sqrt (81)
x = 7/8 +/- 9/8
x = 16/8 or -2/8 wow, nice polite numbers
x = 2 or - 1/4
algebra - Use the quadratic formula to solve the equation. x^2-7x-6=0
algebra - Use the quadratic formula to solve the equation. -4x^2-3x+2=0 Can ...
algebra - which quadratic formula would be used to solve the following quadratic...
Algebra - Can you pleas Solve the quadric equation step by step 4x square =13x+...
math help - write the quadratic equation whose roots are -4 and -5 and whose ...
algebra II - I'm quite clueless as to how to solve this. I know the ...
algebra - solve the polynomial y=2x^2-4x+1 For Further Reading algebra - Reiny, ...
math - use the quadratic formula to solve this equation. 4x^2-8x+3=5 use the ...
Math - Use the quadratic formula to solve each of the following quadratic ...
algebra - Solve equation using quadratic formula x^2+4x+3=0 is answer 3,1 ?
For Further Reading