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Algebra II

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Solve: 4-1/b<3/b

  • Algebra II - ,

    I assume you mean
    4 - (1/b) < 3/b
    Add 1/b to both sides and the < stays the same direction
    4 < 4/b
    1 < 1/b
    Multiply both sides by b. Different rules apply about the < sign depending upon the sign of b.
    If b is positive, b < 1. So 0<b<1 is one solution region.
    If b is negative, b > 1 (which is a contradiction)
    Therefore the only answer is 0<b<1

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