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April 19, 2014

April 19, 2014

Posted by **Lucy** on Saturday, March 8, 2008 at 7:28pm.

- Algebra II -
**drwls**, Saturday, March 8, 2008 at 7:45pmI assume you mean

4 - (1/b) < 3/b

Add 1/b to both sides and the < stays the same direction

4 < 4/b

1 < 1/b

Multiply both sides by b. Different rules apply about the < sign depending upon the sign of b.

If b is positive, b < 1. So 0<b<1 is one solution region.

If b is negative, b > 1 (which is a contradiction)

Therefore the only answer is 0<b<1

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