Algebra-Graphing Linear Equation
posted by G on .
The way I unerstand from the book to graph this equation. I would start at
the Y intersect and go up to 1. The go up 2 for the slope. Then across 4 on the X axis. The book shows the graph with the coordinates of (1,6) and (0,4). When I do it the way the book explains I do not arrive at these coordinates. Y
X' ' ' ' ' 0 1'2 3'4 5 '
Sorry about my poor looking graph.
To graph inequations (they have < or > or ≥ or ≤ in them), consider the corresponding "equation" which will become the boundary of the region you are graphing
So we would be dealing with
y = 2x + 4
put in x=1 ----> y = 2(1)+4 = 6
put in x=0 ----> y = 2(0)+4 = 4
that is how they got the two points (1,6) and (0,4)
Plot these two points, draw a dotted line, and shade in the region below that line.
for y > .... shade in above the dotted line
for y ≥ ....draw a solid line and shade in the region above
for y < .... shade in the region below, like your problem
for y ≤ .... draw a solid line, then shade in below