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April 18, 2014

April 18, 2014

Posted by **G** on Saturday, March 8, 2008 at 6:04pm.

The way I unerstand from the book to graph this equation. I would start at

the Y intersect and go up to 1. The go up 2 for the slope. Then across 4 on the X axis. The book shows the graph with the coordinates of (1,6) and (0,4). When I do it the way the book explains I do not arrive at these coordinates. Y

-7

-6* (1,6)

-5

(0,4)*-4

-3

-2

-1

X' ' ' ' ' 0 1'2 3'4 5 '

Sorry about my poor looking graph.

- Algebra-Graphing Linear Equation -
**Reiny**, Saturday, March 8, 2008 at 6:51pmTo graph inequations (they have < or > or ≥ or ≤ in them), consider the corresponding "equation" which will become the boundary of the region you are graphing

So we would be dealing with

y = 2x + 4

put in x=1 ----> y = 2(1)+4 = 6

put in x=0 ----> y = 2(0)+4 = 4

that is how they got the two points (1,6) and (0,4)

Plot these two points, draw a dotted line, and shade in the region below that line.

for y > .... shade in above the dotted line

for y ≥ ....draw a solid line and shade in the region above

for y < .... shade in the region below, like your problem

for y ≤ .... draw a solid line, then shade in below

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