Friday

August 1, 2014

August 1, 2014

Posted by **does it matter at this point?** on Friday, March 7, 2008 at 9:42pm.

tan^2x+1=sec^2x

(-4/5)^2+1=sec^2x

16/25+1=sec^2x

17/25=sec^2x

sqrt 17/5

I don't know if it should be positive or negative.

- Trig -
**Reiny**, Friday, March 7, 2008 at 9:52pmYou are in the fourth quadrant

the secant has the same sign as the cosine, and in the fourth quadrant the cosine is positive,

Your answer is not correct

Here is an easier way than trying to use the formula you tried.

sinß = y/r = -4/5

so x^2 + (-4)^2 = 5^2

x = ±3 but you are in the fourth quadr, so x=+3

sec x = 1/cosx = 1/(3/5) = 5/3

**Related Questions**

Integration - Intergrate ¡ì sec^3(x) dx could anybody please check this answer. ...

calculus - find dy/dx y=ln (secx + tanx) Let u= secx + tan x dy/dx= 1/u * du/dx ...

Calculus 12th grade (double check my work please) - 2- given the curve is ...

calculus (check my work please) - Not sure if it is right, I have check with the...

calculus - Integrate: dx/sqrt(x^2-9) Answer: ln(x + sqrt(x^2 - 9)) + C I'm ...

Calculus AP - I'm doing trigonometric integrals i wanted to know im doing step ...

Calculus - Integration - Hello! I really don't think I am understanding my calc ...

Calculus - could anybody please explain how sec x tan x - ¡ì sec x tan^2(x) dx...

Calculus PLEASE check my work , - 1.) which of the following represents dy/dx ...

Calculus 12th grade (double check my work please) - 1.) which of the following ...