Tuesday

January 27, 2015

January 27, 2015

Posted by **Miley** on Friday, March 7, 2008 at 5:48pm.

(-81)^3/4

- alg. 2 -
**drwls**, Friday, March 7, 2008 at 6:02pmBecause -81^3 is a negative number. If you take a 1/4 root of any negative number (which is the same thing as taking a square root twice), you get imaginary or complex (real + imaginary) numbers.

- alg. 2 -
**Damon**, Friday, March 7, 2008 at 6:02pmthe third power of -81 is a negative number

you can not take a square root of a negative number and get a real number.

(1/4) power is square root of square root.

**Answer this Question**

**Related Questions**

alg.2 - why is this answer no real root? -5x^6=320?

alg 2+urgent please. - 2/the 6th root of 81 the answer gave an answer of "2 3rd ...

alg 2 - why are these answers no real root? (-81)^3/4 -5X^6=320

algebra - Determine the value(s) of k for which x^2+(k-2)x-2k=0 has equal and ...

Algebra II - Which describes the number and type of roots of the equation x^2 -...

Math - For what value of k does the equation x2 + k = kx – 8 have: Two distinct ...

Math - How many real roots does f(x) = x^3+5x+1 have? x^3 = odd polynomial = at ...

Math - When Synthetically dividing to find a real root out of all Possible Roots...

alg. 2 - a little three square root 4/ little 6 root 16. the answer is one. how ...

maths2 - Use the discriminant to determine the number of real roots the equation...