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December 20, 2014

December 20, 2014

Posted by **shan** on Friday, March 7, 2008 at 7:35am.

- physics -
**drwls**, Friday, March 7, 2008 at 7:57amLet X be the horizontal distance from A to the point above B. Let Vs be the sound speed and Vb be the plane's velocity at point B.

The time required for the plane to fly the distance X is 2X/(164 + Vb), assuming constant acceleration, since (Vb+164)/2 is the average velocity. That equals the time required for the sound to go from A to B, which is X/(Vs*cos36)

Therefore

2/(164+Vb) = 1/Vs*cos36

0.809 Vs = 82 + Vb/2

Vb = 1.608 Vs -168

The sound speed is Vs = 343 m/s, so

Vb = 383 m/s

That is a lot of accleration, going from mach 0.5 to about 1.1

- physics -
**Harry**, Wednesday, November 17, 2010 at 12:39pmAngle's actually 56 degrees...

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