Posted by shan on Friday, March 7, 2008 at 7:35am.
Let X be the horizontal distance from A to the point above B. Let Vs be the sound speed and Vb be the plane's velocity at point B.
The time required for the plane to fly the distance X is 2X/(164 + Vb), assuming constant acceleration, since (Vb+164)/2 is the average velocity. That equals the time required for the sound to go from A to B, which is X/(Vs*cos36)
Therefore
2/(164+Vb) = 1/Vs*cos36
0.809 Vs = 82 + Vb/2
Vb = 1.608 Vs -168
The sound speed is Vs = 343 m/s, so
Vb = 383 m/s
That is a lot of accleration, going from mach 0.5 to about 1.1
Angle's actually 56 degrees...
Related Questions
Math - In this diagram, one person is standing at point A, one person is at ...
Physics - A small plane flying horizontally 150m above the ground at a constant ...
physics - A fighter-jet is in level flight at an altitude of 400m and with a ...
physics - 1. A jet is flying with an air speed of 500 m/s. A parcel is dropped ...
physics - 1. A jet is flying with an air speed of 500 m/s. A parcel is dropped ...
college physics - A fighter-jet is in level flight at an altitude of 400m and ...
Dynamics, Math - a plane is flying horizontally at an altitude of 420m. A bomb ...
Dynamics, Math - a plane is flying horizontally at an altitude of 420m. A bomb ...
grade 11 physics - A bomber flying horizontally at 250 m/s releases a bomb 1500m...
Physics - A skateboarder shoots off a ramp with a velocity of 6.5 m/s, directed ...
For Further Reading