Posted by **Jon** on Thursday, March 6, 2008 at 3:30pm.

Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).

(0 is not the number zero I don't know what its called)

I have to find r first.

r=sqrt x^2+y^2

r=sqrt -5^2+-4^2

r=sqrt 41

sin=y/r

sin=-4/sqrt 41

cos=x/r

cos=-5/sqrt 41

tan=y/x

tan=-4/-5

csc=r/y

csc=sqrt 41/-4

sec=r/x

sec=sqrt 41/-5

cot=x/y

cot=-5/-4

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