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April 20, 2014

April 20, 2014

Posted by **Joy** on Wednesday, March 5, 2008 at 10:35pm.

a) If the perimeter of the copy is 36 meters, find the perimeter of the original triangle using the proportion 10/3.

b) If the area of the copied triangle is 48 meters squared, use a proportion to find the area of the original triangle.

Please HELP me! I don't really know how I can solve this...

- Pre-Algebra -
**Samantha**, Thursday, March 6, 2008 at 1:10am( copy/ orginal) = 10/3

(10/3)=(copy perimeter)/(orig.perimeter)

(10/3)=(36/X)

cross multiply and you get

10x=108 then x= 10 4/5 =10.8

x=perimeter of org.

triangle

Do the same with part b but this time it's area.

(10/3)=(48/x) ===> x= 14 2/5 =14.4

- Pre-Algebra(second part is wrong) -
**Reiny**, Thursday, March 6, 2008 at 7:54amSamantha, your second part is not correct

The area of similar figures is proportional to the**square**of their sides. Since perimeter is a function of the sides you last line should have been

(10/3)^{2}=(48/x) ===> x= 4.32

- Pre-Algebra(second part is wrong) -

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