Posted by Anonymous on Wednesday, March 5, 2008 at 10:23pm.
First you need to look up the index or refraction for air and water, the two materials in which the light will travel and refract.
Air has a refractive index of N2 = 1.0003, and water has a refractive index of N1 = 1.333. I use index 2 for air because it is the second medium the light passes through; water is the first.
The angle of incidence A1 for the light beam in the water is tan^-1 1.7/2.9 = tan^-1 0.5862 = 30.37 degrees.
The last step is to use Snell's law:
N1 sin A1 = N2 sin A2
Solve for the angle of refraction, A2
Sin A2 = 0.5057*(1.333/1.0003)= 0.6739
A2 = ?
Related Questions
physics - In searching the bottom of a pool at night, a watchman shines a narrow...
Physics - A swimming pool filled with water to its edge, the depth of the water ...
physics - A high fountain of water is located at the center of a circular pool ...
physics - A high fountain of water is located at the center of a circular pool ...
Physics - A person lying at poolside looks over the edge of the pool and sees a ...
spanish - how do you say pool in spanish? piscina = pool charca is pool If you ...
Physics - An Olympic swimming pool is heated and maintained at 30 °C in the ...
phys101 - a homeowner wishes to drain her swimming pool by siphoning the water,...
physics - when you dive from atop a tall flagpole into a swimming pool below. ...
Physics - Estimate Olympic swimming pool problem using Order of Magnitude ...
For Further Reading
