Posted by **Anonymous** on Wednesday, March 5, 2008 at 10:23pm.

A light source, S, is located 2.9 m below the surface of a swimming pool and 1.7 m from one edge of the pool. The pool is filled to the top with water. At what angle does the light reaching the edge of the pool leave the water?

- Physics -
**drwls**, Thursday, March 6, 2008 at 4:30am
First you need to look up the index or refraction for air and water, the two materials in which the light will travel and refract.

Air has a refractive index of N2 = 1.0003, and water has a refractive index of N1 = 1.333. I use index 2 for air because it is the second medium the light passes through; water is the first.

The angle of incidence A1 for the light beam in the water is tan^-1 1.7/2.9 = tan^-1 0.5862 = 30.37 degrees.

The last step is to use Snell's law:

N1 sin A1 = N2 sin A2

Solve for the angle of refraction, A2

Sin A2 = 0.5057*(1.333/1.0003)= 0.6739

A2 = ?

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