Posted by Alex on Wednesday, March 5, 2008 at 9:34pm.
For #1.
I do these this way. The dashed lines represent the voltage for the reduction reactions shown.
--------- Cl2 + 2e ==> 2Cl^-   +1.4
--------- Hg^+2 + 2e ==> Hg   +0.85
--------- 2H^+ + 2e ==> H2   0.0
The spacing is arbitrary; I just put the vertical spacing between the dashed lines to show how I do it. Normally, you see, the standard H cell is 0 voltage and the Cl2 reduction potential is +1.4 volts above H. The difference between 1.4 and 0 is of course 1.4 volts. Now if we replace that H reference cell with a mercury(II)/Mercury cell, that is +0.85 with reference to H. So the Cl2 potential measured against the Mercury as a reference cell will be 1.4 - 0.85 = 0.55 volts. These number I am using are from an OLD OLD text I had in graduate school and you need to look in your text/notes and pick up the up to date numbers. I hope this helps. I think the drawing with the dashed lines is the only way I can see how to do these. It may or may not help you.
I don't know your trouble with the Zn/Ni cell. I don't understand the last problem.
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