Homework Help: physics

Posted by Andrea on Wednesday, March 5, 2008 at 5:28pm.

An electric charfe of -3 C is moved from a position where the electric potential is 1 V to a position where the electric potential is -6V. What is the chsange in potential energy of the charge with this change in position?

I know that change in
PE = k(q1q)/r_2 - k(q1q)/r_1

I am having trouble figuring out what the distance or r would be for this problem.

physics - bobpursley, Wednesday, March 5, 2008 at 5:35pm
Potential difference is 5 volts.

Potential energy difference is 5Q, and Q is given.

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