Thursday

April 24, 2014

April 24, 2014

Posted by **Jon** on Wednesday, March 5, 2008 at 2:30pm.

It might be a little out of order but this is what I got.

C(10,2)

(10*9*8*7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1*2*1)

=45

C(6,2)

(6*5*4*3*2*1)/(2*1)

=360

C(4,2)

(4*3*2*1)/(2*1

=12

360*12 = 4320

s/s+f

4320/4320+45

4320/4365

99% answer

- Algebra -
**Jon**, Wednesday, March 5, 2008 at 3:21pmno how about this

P(at least 2 women)=

P(exactly 2 women)+P(exactly 3 women)=

{(6!/(1!*5!))*(4!/(2!*2!))+

(4!/(3!*1!)}/{10!/(3!*7!)}=

40/120=1/3

answer = 1/3

**Related Questions**

math - from a group of women and 4 men, determine in how many ways a committee ...

gr12 math - froma group of 6 ladies and 4 men, determine in how many ways a ...

math - In a group of 7 men and 8 women, how many committees of 5 can be selected...

math - a committee of 5 people is to be selected from a group of 6 men and 9 ...

math prob - A committee of 5 people is selected from a group of 7 men and 9 ...

statistics permutations and combinations - Selecting a committee: There are 7 ...

math - A committee of 4 is chosen from a group of 10 women and 6 men. Determine ...

algebra - A 4-person leadership committee is randomly chosen from a group of 24 ...

math word problem - There are 10 women and 8 men in a club. How many different ...

algebra ll - from a group of 6 men and 4 women , a committe of 3 is to be ...