Posted by **Jon** on Wednesday, March 5, 2008 at 2:30pm.

From a group of 6 men and 4 women, a committee of 3 is to be selected at random. Find P(at least 2 women).

It might be a little out of order but this is what I got.

C(10,2)

(10*9*8*7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1*2*1)

=45

C(6,2)

(6*5*4*3*2*1)/(2*1)

=360

C(4,2)

(4*3*2*1)/(2*1

=12

360*12 = 4320

s/s+f

4320/4320+45

4320/4365

99% answer

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