Posted by Nazharia on Wednesday, March 5, 2008 at 9:36am.
Make a neat diagram.
Label the bottom of the tree R and its top T
You should have two right angled triangles, PTR and QTR
Label PQ = 10, let QR = x and RT = h
In triangle QRT, tan 32º=h/x
h = xtan32
in triangle PTR, tan 23º = h/(x+10)
so h = (x+10)tan23
equate the two equations, (both are h=...)
xtan32 = (x+10)tan23
xtan32 = xtan23 + 10tan23
xtan32 - xtan23 = 10tan23
x(tan32-tan23) = 10tan23
x = 10tan23/(tan32-tan23)
Now you could solve for x now, and sub that back into
h = xtan32
I got h = 13.24, let me know if you got the same answer.
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