ok it says give the formula for this one Hydronitric acid, I put H3N
For Iron (III) chloride I put Fe3Cl
Silver acetrate i put AG1C2
Ca(OH02 i put calcium oxide
for CCL4 I had no clue
Mercury (II) oxide i put HG2O
NaClO3 I put Sodium chlorate
for (NH4)2SO4 i put hydronitrate Sodium
Fe2S3 I put Iron sulfrate
right on the hydronitric acid.
right on sodium chlorate
wrong on the others.
What does Iron(III) mean? does it mean Fe+3?
what is a tetrachloride?
what is ammonium?
on the last, you have to put in the II or III on the iron, and it is a sulfide, not sulfate. You need to memorize the polyatomic ions.
FeCl3
AgC2H3O2
carbon tetrachloride this is CCl4 right?
HgO
ammonium sulfate
iron(III)sulfide
alright now all I need help with is Ca (OH)2
all ok, calcium hydroxide. Memorize those polyatomic ions.
It seems like you have attempted to write the formulas for various chemical compounds, but some of them are incorrect. I'll guide you through the correct formulas for each compound:
1. Hydronitric Acid:
The formula for hydronitric acid is not H3N. It is actually HNO3. To obtain this formula, you should recognize that hydronitric acid is composed of hydrogen (H) and the nitrate ion (NO3). The nitrate ion is a polyatomic ion composed of one nitrogen atom (N) and three oxygen atoms (O). Thus, combining the hydrogen ion (H+) with the nitrate ion (NO3-) gives you HNO3.
2. Iron (III) Chloride:
Your attempt, Fe3Cl, is close but not quite there. The correct formula for iron (III) chloride is FeCl3. To determine the formula, you must recognize that iron (III) refers to the iron cation with a charge of +3 (Fe^3+), while chloride is the anion with a charge of -1 (Cl^-). To balance the charges between the iron and chloride, you need three chloride ions to combine with one iron ion, resulting in FeCl3.
3. Silver Acetate:
Your attempt, AG1C2, has a minor error. The correct formula for silver acetate is AgC2H3O2. To arrive at this formula, you should recognize that silver is represented by Ag, and acetate is a polyatomic ion composed of two carbon atoms (C), three hydrogen atoms (H), and two oxygen atoms (O). Therefore, combining the silver ion (Ag+) and the acetate ion (C2H3O2-) gives AgC2H3O2.
4. Calcium Hydroxide:
Your attempt, Ca(OH02), has a mistake. The correct formula for calcium hydroxide is Ca(OH)2. To determine this formula, you should recognize that calcium is represented by Ca, and hydroxide is a polyatomic ion composed of one oxygen atom (O) and one hydrogen atom (H). Therefore, combining one calcium ion (Ca^2+) with two hydroxide ions (OH-) gives Ca(OH)2.
5. Carbon Tetrachloride (CCI4):
Carbon tetrachloride, commonly known as CCl4, has the same formula as you stated. So, CCl4 is correct.
6. Mercury (II) Oxide:
Your attempt, HG2O, is not accurate. The correct formula for mercury (II) oxide is HgO. To obtain this formula, you should recognize that mercury (II) refers to the mercury cation with a charge of +2 (Hg^2+), while oxide is the anion with a charge of -2 (O^2-). To balance the charges between mercury and oxide, you need one mercury ion to combine with one oxide ion, resulting in HgO.
7. Sodium Chlorate:
Your attempt, NaClO3, is correct! Sodium chlorate is indeed represented by that formula.
8. Ammonium Sulfate ((NH4)2SO4):
Your attempt, hydronitrate sodium, is incorrect. The correct formula for ammonium sulfate is (NH4)2SO4. To determine this formula, you should recognize that ammonium is a polyatomic ion composed of one nitrogen atom (N) and four hydrogen atoms (H). Sulfate is also a polyatomic ion composed of one sulfur atom (S) and four oxygen atoms (O). Therefore, combining two ammonium ions ((NH4)+) with one sulfate ion (SO4^2-) gives (NH4)2SO4.
9. Iron (III) Sulfide:
Your attempt, Iron sulfrate (Fe2S3), is incorrect. The correct formula for iron (III) sulfide is Fe2S3. To determine this formula, you should recognize that iron (III) refers to the iron cation with a charge of +3 (Fe^3+), while sulfide is the anion with a charge of -2 (S^2-). To balance the charges between iron and sulfide, you need two iron ions to combine with three sulfide ions, resulting in Fe2S3.