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April 19, 2014

April 19, 2014

Posted by **aa** on Tuesday, March 4, 2008 at 7:44pm.

cos(x-(pi/4))+sin(x-(pi/4))=1

Find the answer from 0 to 2pi.

When I slove this, I got

cosx+sinx=(1/ square root of 2).

then I don't know what to do the rest. Please help me.

- pre-cal/trig -
**emily**, Tuesday, March 4, 2008 at 7:48pmif you get to cosx+sinx=1/square root of 2, well we are doing identities in my pre-cal class and cosx+sinx always equals 1, so it would be 1/square root of 2.

- pre-cal/trig -
**aa**, Tuesday, March 4, 2008 at 8:25pmSorry, cosx+ sinx is not equal to 1 (from the identites). But, it was like this:

(sinx)^2+ (cosx)^2= 1

- pre-cal/trig -
- pre-cal/trig -
**^quen^**, Tuesday, March 4, 2008 at 8:54pmCan Anybody answer this question for me???? Please???

PlEASE hlep me with this!! I need it as soon as possible.......

cos(x-(pi/4))+sin(x-(pi/4))=1

Find the answer from 0 to 2pi

- pre-cal/trig -
**^quen^**, Wednesday, March 5, 2008 at 8:23amsquare both side:

(cosx+sinx)^x=(1/square root of 2)

then solve: it will work.

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