precal/trig
posted by aa .
PlEASE help me with this!! I need it as soon as possible.......
cos(x(pi/4))+sin(x(pi/4))=1
Find the answer from 0 to 2pi.
When I slove this, I got
cosx+sinx=(1/ square root of 2).
then I don't know what to do the rest. Please help me.

if you get to cosx+sinx=1/square root of 2, well we are doing identities in my precal class and cosx+sinx always equals 1, so it would be 1/square root of 2.

Sorry, cosx+ sinx is not equal to 1 (from the identites). But, it was like this:
(sinx)^2+ (cosx)^2= 1 
Can Anybody answer this question for me???? Please???
PlEASE help me with this!! I need it as soon as possible.......
cos(x(pi/4))+sin(x(pi/4))=1
Find the answer from 0 to 2pi 
square both side:
(cosx+sinx)^x=(1/square root of 2)
then solve: it will work.