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April 18, 2014

April 18, 2014

Posted by **Jon** on Tuesday, March 4, 2008 at 12:50pm.

an+1=3an+1

a1+1=3a1+1

a2=3(5)+1

a2=16

a2+1=3a2+1

a3=3(16)+1

a3=49

a3+1=3a3+1

a4=3(49)+1

a4=148

a4+1=3a4+1

a5=3(148)+1

a5=445

so the first five terms are: 5,16,49,148,445

- Math -
**Reiny**, Tuesday, March 4, 2008 at 1:05pmYour answer is correct, but I am having difficulty following your notation.

How about instead of an+1=3an+1 something like

term(n+1) = 3term(n) + 1

- Math -
**Jon**, Tuesday, March 4, 2008 at 1:32pmok

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