Posted by Anna-Marie on Monday, March 3, 2008 at 10:30pm.
A right triangle with largest side 20 would have
x^2 + (x+4)^2 = 400
x^2 + 4x + 8 = 200
x^2 + 4x -192 = 0
(x-12)(x+16) = 0
The only root that makes sense (by being positive) is x = 12. That means that you have a right triangle if the sides are 12 and 16. (The x = 12 case). If x>12, the triangle is acute, meaning thet the largest angle is less than 90 degrees. If x<12, it is obtuse. You should be able to convince yourself of that by drawing the figure or by using the law of cosines.
i hate your guy's page bacause it dosnt come up and say the value of a skinny and a bit
It is not obtuse; it is impossible because one side is longer than the sum of the other two.
You also posted this problem separately. I gave a more complete answer there.
Let the first side be A, the second side b and the third side C.
Note that
(x^2 - y^2)^2 + (2xy)^2 = x^4 + 2x^2y^2 + y^2 = (x^2 + y^2)^2
Therefore the relationship A^2 + B^2 = C^2 is obeyed. This is only true for a right triangle.
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