Posted by Andrea on .
A block oscillates on a spring and passes its equilibrium position with a speed of .157m/s. It's kinetic energy is zero when the block is at the distance of .1m from equilibrium. Assume no friction between the block and the table.
KE =0J when x=.1m
a)First I need to find the period of the oscillation:
1/2 mv^2=1/2 k (.1)^2
solve for m/k
b) what's the mass displacement from the equilibrium when its velocity v=v_mx/2?
c) what's the spring constant if the restoring force acting on the mass when its velocity v=v_max/2 is 8.67N?
d) what's the acceleration of the mass when v=v_max/2?:
i know that F=ma
Given that m/k= .405 and k=100 N/m to find m would I mulitiply .405 by 100 This would give me 40.5kg.
Finally to solve the problem a=8.67N/40.5kg= .21m/s
e)What is the KE of the mass when velocity v= v_max/2?
f)What is the PE of the mass when velocity v= v_max/2?
Are these correct?