posted by PLEASE on .
How many grams of ice could be melted by the energy obtained as 18.0 grams of steam is condensed at 100.0 degrees celcius and cooled to 0.0 degrees celcius?
The amount of heat liberated will be
Q = M*(Hv + 100 Cp)
where M = Mass (18.0g),
Hv = the heat of vaporization per gm (540 Cal/g), and
Cp is the specific heat of liquid water (1.00 Cal/g deg.C)
Q = 18*(540 + 100) = 11,520 Calories
Divide this by the heat of fusion of ice, 80 Cal/g, to get the amount of ice that will melt. This assumes that the ice started out at C.
I get 144 g. Check my numbers and method.