what precipitate (if any) will form? Al(NO3)3 (aq) + Ba(OH)2 (aq)
Al(OH)3 will ppt. A white, gelatinous ppt.
Well, let's see... Al(NO3)3 (aq) and Ba(OH)2 (aq) are both aqueous solutions. When they react, a double displacement reaction occurs, which means the positive ions in one compound swap with the positive ions in the other compound.
In this case, aluminum nitrate (Al(NO3)3) contains the aluminum ion (Al3+) and the nitrate ion (NO3-), while barium hydroxide (Ba(OH)2) contains the barium ion (Ba2+) and the hydroxide ion (OH-).
When Al(NO3)3 and Ba(OH)2 combine, they form aluminum hydroxide (Al(OH)3) and barium nitrate (Ba(NO3)2).
Now, as for your question on precipitate formation, aluminum hydroxide is considered insoluble in water, which means it forms a precipitate when it combines with water. So, the answer is yes, a precipitate of aluminum hydroxide (Al(OH)3) will form. Keep your eyes peeled for those tiny, solid flakes of humorless aluminum hydroxide!
To determine if a precipitate will form when Al(NO3)3 (aq) and Ba(OH)2 (aq) are mixed, we need to identify the products and then check if one of them is insoluble.
First, let's write the balanced equation for the reaction:
Al(NO3)3 (aq) + 3Ba(OH)2 (aq) → Al(OH)3 (s) + 3Ba(NO3)2 (aq)
By examining the solubility rules, we can determine if any of the products are insoluble and will form a precipitate.
According to the rules, most nitrates (NO3-) are soluble, so Ba(NO3)2 is soluble. Therefore, it remains in the aqueous (aq) state.
On the other hand, hydroxides (OH-) are generally insoluble except for those of the alkali metals (Group 1A) and Ba(OH)2. Aluminum hydroxide (Al(OH)3) is also an insoluble hydroxide.
As a result, when Al(NO3)3 (aq) and Ba(OH)2 (aq) are mixed, a white precipitate of aluminum hydroxide (Al(OH)3) will form.
To determine if a precipitate will form when Al(NO3)3 (aq) reacts with Ba(OH)2 (aq), we need to use solubility rules to identify if any of the possible products are insoluble.
First, we can write out the balanced chemical equation for the reaction:
Al(NO3)3 (aq) + 3Ba(OH)2 (aq) → Al(OH)3 (s) + 3Ba(NO3)2 (aq)
Next, we look at the solubility rules to determine if Al(OH)3 is insoluble. According to the rules:
- Hydroxides (OH-) are generally insoluble except for Group 1A ions (Li+, Na+, K+, etc.) and some larger 2A ions (Ca2+, Sr2+, Ba2+).
- Aluminum (Al3+) is not one of the exceptions.
Based on the solubility rules, Al(OH)3 is insoluble. Therefore, it will form as a precipitate.
To summarize, when Al(NO3)3 (aq) reacts with Ba(OH)2 (aq), Al(OH)3 (s) will form as a precipitate.