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September 19, 2014

September 19, 2014

Posted by **Anonymous** on Sunday, March 2, 2008 at 9:49pm.

- calculus -
**drwls**, Sunday, March 2, 2008 at 10:14pmIf x is her horizontal distance from the street light, the shadow length s is given by

s = (5.5/22)*(s + x)

so

(16.5/22)s = (5.5/22) x

s = x/3

Therefore ds/dt = (1/3) dx/dt

= (2.0 ft/s)*(dx/dt)

- calculus -
**Mona**, Thursday, January 31, 2013 at 1:13am-2

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