Posted by Anonymous on .
You are using Newton's method to solve x^3-5x-2=0. If your first guess is X1=2, what value will you calculate for the next approximation X2?
your equation would be
xnew = x - (x^3 - 5x - 2)/(3x^2 - 5)
so for x=2
xnew = 2 - (8-10-2)/(12-5)
Incidentally, my next 4 answers were
2.4142136 which would be one of the answers correct up to 7 decimal places.