Homework Help: calculus

Posted by Anonymous on Sunday, March 2, 2008 at 9:42pm.

You are using Newton's method to solve x^3-5x-2=0. If your first guess is X1=2, what value will you calculate for the next approximation X2?

calculus - Reiny, Sunday, March 2, 2008 at 11:29pm
your equation would be

x_new = x - (x^3 - 5x - 2)/(3x^2 - 5)

so for x=2
x_new = 2 - (8-10-2)/(12-5)
= 2.5714

Incidentally, my next 4 answers were

2.4268029
2.4143045
2.4142136 and
2.4142136 which would be one of the answers correct up to 7 decimal places.

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