calculus
posted by Anonymous on .
You are using Newton's method to solve x^35x2=0. If your first guess is X1=2, what value will you calculate for the next approximation X2?

your equation would be
x_{new} = x  (x^3  5x  2)/(3x^2  5)
so for x=2
x_{new} = 2  (8102)/(125)
= 2.5714
Incidentally, my next 4 answers were
2.4268029
2.4143045
2.4142136 and
2.4142136 which would be one of the answers correct up to 7 decimal places.