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December 22, 2014

December 22, 2014

Posted by **Anonymous** on Sunday, March 2, 2008 at 9:36pm.

- calculus -
**Reiny**, Sunday, March 2, 2008 at 11:34pmlet the point of contact of the rectangle with the parabola in the first quadrant be P(x,y)

So the base of the rectangle is 2x and its height is y

Area = 2xy

= 2x(2-x^2)

= 4x = 2x^3

d(Area)/dx = 4 - 6x^2 = 0 for a max/min of area

6x^2 = 4

x = √(2/3)

then the height for a max area

= 2 - 2/3

= 4/3

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