Posted by sTELLA on Sunday, March 2, 2008 at 7:23pm.
Three moles of an ideal gas are compressed from 5.5*10^2 to 2.5*10^2 m^3. During the compression, 6.1*10^3J of work is done on the gas, and heat is removed to keep the temperature of the gas constant at all times. Find the temperature of the gas.
I posted this question few hours ago, and someone gave me such hints to do it. However, I don't quite get it, can anyone please explain more about it?THANKS A LOT!
p V = n R T is state equation before and after
Now work done at constant temp
dW = p dV
but p = (n R T)/V and here n R T is constant given
so
dW = (nRT) dV/V
so
work done = (nRT) ln(V1/V2)
by the way, that is also the heat out since internal energy depends only on T which is constant.

PHYSICS  Damon, Sunday, March 2, 2008 at 7:40pm
Stella,
I assumed that you have had calculus.
If you have not, then your book must say something like:
For an ideal gas:
With compression at constant temperature,
work in = (n R T) ln (V1/V2)
or
With compression at constant temperature
heat out = (n R T) ln (V1/V2)
Since change in internal energy = heat in  work out
and internal energy depends only on temperature
your work in is the same as the heat out
You are given the work in, so you have :
work in
n, number of moles
R gas constant
V1 and V2
so you can calculate T 
PHYSICS  sTELLA, Sunday, March 2, 2008 at 7:48pm
work in = (n R T) ln (V1/V2)
what is the "1n" standing for? 
PHYSICS  Damon, Sunday, March 2, 2008 at 7:50pm
ln is natural log. Log to the base e. It is on your calculator, probably on the same key as e^x

PHYSICS  Damon, Sunday, March 2, 2008 at 7:55pm
This must be in your physics book. Look in the index for isothermal compression or expansion or simply compression or expansion. It may be in a paragraph on "work done during volume changes".