posted by sTELLA on .
Three moles of an ideal gas are compressed from 5.5*10^-2 to 2.5*10^-2 m^3. During the compression, 6.1*10^3J of work is done on the gas, and heat is removed to keep the temperature of the gas constant at all times. Find the temperature of the gas.
Can anyone please give me some hints to do this?THANKS A LOT!
p V = n R T is state equation before and after
Now work done at constant temp
dW = -p dV
but p = (n R T)/V and here n R T is constant given
dW = -(nRT) dV/V
work done = (nRT) ln(V1/V2)
by the way, that is also the heat out since internal energy depends only on T which is constant.
i don't get it...where does the d come from?