Posted by Jon on Sunday, March 2, 2008 at 5:13pm.
Identify the vertex, axis of symmetry, and direction of opening for y=2(x+3)^25
y = 2x+3^25
h = 3
k = 5
vertex = (3,5)
axis of symmetry = x = 3
direction = up b/c a = 2 and 2>0

Algebra II  Damon, Sunday, March 2, 2008 at 5:24pm
y = 2 (x+3)^2  5
(x+3)^2 = (1/2)(y+5)
(x+3)^2 = 4 (1/8) (y+5)
vertex (3,5)
symmetric about x = 3
indeed opens up because a = +1/8, check as x becomes very positive or very negative, y gets big positive

Algebra II(can you explain)  Jon, Sunday, March 2, 2008 at 5:41pm
I don't understand what you did after the 1st line.

Algebra II  Damon, Sunday, March 2, 2008 at 7:16pm
Hmmm
I know, and I bet it is in your book, that
a formula of type:
(xh)^2 = 4 a (yk)
is a parabola with vertex at (h,k)
a is the distance from vertex to focus and from vertex to directrix
if a is +, opens up. if a is , opens down
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