Saturday

August 30, 2014

August 30, 2014

Posted by **Mike** on Sunday, March 2, 2008 at 4:34pm.

- Math -
**Damon**, Sunday, March 2, 2008 at 4:58pmp = .65

(1-p) = .35

binomial distribution, n = 3

binomial coefs for n = 3 are 1, 3, 3, 1

probability of three women, zero men in three = coef(3,0)(p)^3 (1-p)^0

= 1 (.65)^3 (1)

= .2746 = 27%

- Math -
**Damon**, Sunday, March 2, 2008 at 5:00pmOf course I made this too hard. Since it is the trivial case of all the same, not for example two men and one woman, you could just say 3 independent events each with a probability of .65 or .65^3

- Math -

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