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January 29, 2015

January 29, 2015

Posted by **Lucy** on Sunday, March 2, 2008 at 4:16pm.

I cannot find any example in my book that works a problem with the vertex, all of the examples that I have to go by give only the focus and directrix.

Thanks.

- Algebra II -
**Damon**, Sunday, March 2, 2008 at 4:48pmSince this parabola has vertex to the left and at the same level as the focus, it opens right and is of form:

(y-k)^2 = 4 a (x-h)

the vertex is at (h,k)

distance from vertex to focus = a

distance from vertex to directrix = a

here, vertex at (0,3)

so (y-3)^2 = 4 a (x)

since a is distance from vertex to focus

(y-3)^2 = 4*1 x = 4 x

so

x = (1/4)(y^2 - 6 y + 9)

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