Algebra II
posted by Lucy .
Determine the equation of any vertical asymptotes and the value of x for any holes in the graph: f(x)= x^211x+18/x2.
I factored and got: (x9)(x2)/x2
Answer: no vertical asymptotes and x= 2&7 are the holes.
Is this correct?
Thanks.

The original equation is the same as x9, but becomes 0/0 with a limiting value of 7 at x=2. There is no vertical asymptote and no singularity "hole?" at x=9.

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